
Single-slit diffraction
PHYS 310 · Wave Optics
A single slit produces a diffraction pattern because different parts of the slit interfere. This lesson derives minima, central maximum width, and the connection to resolution.
Key equations
a\sin\theta=m\lambdam=\pm1,\pm2,\pm3,\ldotsa\sin\theta=\lambdaa\sin\theta=\pm\lambda\sin\theta\approx \theta\theta\approx \frac{\lambda}{a}\Delta\theta\approx \frac{2\lambda}{a}I(\theta)=I_0\left(\frac{\sin\beta}{\beta}\right)^2\beta=\frac{\pi a\sin\theta}{\lambda}\theta_{min}=1.22\frac{\lambda}{D}Learning objectives
- Explain why a single slit creates a diffraction pattern.
- Derive the condition for single-slit minima.
- Calculate central maximum width.
- Interpret the single-slit intensity formula.
- Connect diffraction to optical resolution limits.
Diffraction from one opening
Even a single slit produces a pattern of bright and dark regions. This happens because different parts of the slit act as sources of wavelets. Their contributions interfere at the screen.
The result is a broad central maximum with weaker side maxima. This cannot be explained by ray optics alone.
Destructive interference condition
Let the slit width be . For light of wavelength , dark minima occur at angles satisfying
where
There is no minimum because the center is the main maximum.
Why the minima occur
For the first minimum, divide the slit into two halves. At an angle where the path difference between light from corresponding points in the two halves is , every contribution from the top half cancels a contribution from the bottom half.
This gives
For higher minima, the slit can be divided into more pairs or groups that cancel similarly.
Central maximum width
The central maximum extends between the first minima on either side:
For small angles,
so the angular half-width is approximately
hetaapprox rac{lambda}{a}
The full angular width of the central maximum is approximately
Delta hetaapprox rac{2lambda}{a}
A narrower slit produces a wider diffraction pattern.
Intensity pattern
The full intensity pattern is
ight)^2$$ where $$eta=rac{pi asin heta}{lambda}$$ This function has a strong central maximum and weaker side lobes. The minima occur when $sineta=0$ except at $eta=0$. ## Diffraction and resolution Diffraction limits the ability of optical systems to form sharp images. A point source imaged through a circular aperture forms an Airy pattern, not a perfect point. For a circular aperture of diameter $D$, the angular resolution limit is approximately $$ heta_{min}=1.22rac{lambda}{D}$$ Although this formula is for circular apertures rather than slits, the same idea applies: finite aperture causes spreading. ## Slit width tradeoff If the slit is very wide compared with wavelength, diffraction is small and ray optics works well. If the slit is comparable to wavelength, diffraction dominates. This is why visible light, with wavelengths around hundreds of nanometers, diffracts noticeably through very small apertures but not strongly through ordinary doorways. ## Diffraction versus interference Single-slit diffraction and double-slit interference are related. In a real double-slit experiment, each slit has finite width, so the observed pattern is a two-slit interference pattern modulated by a single-slit diffraction envelope. ## The big idea Single-slit diffraction arises from interference among wavelets from different parts of the same slit. Minima occur at $asin heta=mlambda$, and a narrower slit creates a wider diffraction pattern. Diffraction sets fundamental limits on optical resolution.Ask your AI physics guide
Ask anything about Optics and Light — Single-slit diffraction, or choose a suggested question below.
AI responses are educational and may not be perfectly accurate. Press Enter to send, Shift+Enter for new line.